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✓ ANSWER ACCEPTED

Making data in a dictionary correspond?

Asked 166 views1 answers

I've set up this dictionary (I think), where the number is the PlayerLevel, the first string is the PlayerStatus and the second string is the ImageURL...

local dictionary = {
	[1] = {"N O V I C E", "www.url1here"},
	[2] = {"E X P E R I E N C E D", "www.url2here"},
	[3] = {"P R O", "www.url3here"},
}

The player has a leaderstats named PlayerLevel, how would I set up two more variables like so:

local PlayerLevel = Player.leaderstats.PlayerLevel.Value
local PlayerStatus = --?
local ImageURL = --?

The two other variables must correspond to its level.

Anonymous

1 answer

✓ Accepted answer

Good question!

First, I think it's important to point something out.

local tb = { 
	"hello ",
	"there"
} -- this is the same as:

local tb = {
	[1] = "hello ",
	[2] = "there"
}

print(tb[1]..tb[2])

Lua will auto-index things; you don't have to manually put the numbers.

Answer

In your code that I changed to make it shorter by removing the indexes, to get the values from the table you do this:

local dictionary = {
    {"N O V I C E", "www.url1here"},
    {"E X P E R I E N C E D", "www.url2here"},
    {"P R O", "www.url3here"},
}

local PlayerLevel = Player.leaderstats.PlayerLevel.Value
local PlayerStatus = dictionary[PlayerLevel][1]
local ImageURL = dictionary[PlayerLevel][2]
This isn't actually a dictionary.

I hope that helps you!

AnonymousEdited Permalink

5 comments

0

Check when the player levels up and change the variables corresponding to the new level for this to work properly :D

Anonymous#
0

It throws this error where the PlayerStatus variable is: attempt to index field '?' (a nil value)

Anonymous#
0

That means PlayerLevel is nil. Define it properly.

Anonymous#
0

It's working in a Server but not in Studio Test mode, any ideas?

Anonymous#
0

Yeah, use WaitForChild. Example: PlayerLevel = Player:WaitForChild("leaderstats"):WaitForChild("PlayerLevel").Value

Anonymous#

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