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✓ ANSWER ACCEPTED

How can I turn a number into words?

Say you have a number, make it 192,540,520

How can you turn this number into this string: one hundred ninety two million five hundred fourty thousand five hundred twenty

1 answer

✓ Accepted answer

This is a really fun exercise that involves recursion. I highly recommend attempting to work through this problem on your own before simply using the solution I present below. Take your time. Experiment with it. Have fun!

With that said, I present my solution here...

local stringVals = {
	[0] = "",
	[1] = "one",
	[2] = "two",
	[3] = "three",
	[4] = "four",
	[5] = "five",
	[6] = "six",
	[7] = "seven",
	[8] = "eight",
	[9] = "nine",
	[10] = "ten",
	[11] = "eleven",
	[12] = "twelve",
	[13] = "thirteen",
	[14] = "fourteen",
	[15] = "fifteen",
	[16] = "sixteen",
	[17] = "seventeen",
	[18] = "eighteen",
	[19] = "nineteen",
	[20] = "twenty",
	[30] = "thirty",
	[40] = "forty",
	[50] = "fifty",
	[60] = "sixty",
	[70] = "seventy",
	[80] = "eighty",
	[90] = "ninety",
	[100] = "hundred",
	[1000] = "thousand",
}

local groupNames = {
	[1] = "",
	[2] = " thousand ",
	[3] = " million ",
	[4] = " billion ",
}

local function groupToWord(number)
	local result = stringVals[number]
	if not result then
		result = ""
		local hundreds = math.floor(number/100)
		if hundreds > 0 then
			result = result .. stringVals[hundreds] .. " " .. stringVals[100] .. " "
		end
		number = number - hundreds * 100
		local tens = math.floor(number/10)
		number = number - tens * 10
		if tens == 1 and number > 0 then
			--address funny names eleven thru nineteen
			result = result .. stringVals[number + 10]
		else
			if tens > 0 then
				result = result .. stringVals[tens * 10] .. " "
			end
			if number > 0 then
				result = result .. stringVals[number]
			end
		end
	end
	return result
end

local function numberToWords(number, groupIndex)
	if number then
		groupIndex = groupIndex or 1
		local numStr = tostring(number)
		local endStr = numStr:sub(-3)
		local front = numStr:sub(1,-4)
		return numberToWords(tonumber(front), groupIndex + 1) .. groupToWord(endStr) .. groupNames[groupIndex]
	else 
		return ""
	end 
end

for i = 100, 2000, 13 do
	print(i, numberToWords(i))
end

select output:

178 one hundred seventy eight

217 two hundred seventeen

334 three hundred thirty four

555 five hundred fifty five

685 six hundred eighty five

867 eight hundred sixty seven

1010 one thousand ten

1491 one thousand four hundred ninety one

1816 one thousand eight hundred sixteen

1998 one thousand nine hundred ninety eight

192540520 one hundred ninety two million five hundred forty thousand five hundred twenty

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