Scripting Helpers is winding down operations and is now read-only. More info→
Log in to vote
0
How to put 0 in front of any single digit integer?
Say, if I set an integer variable:
local Number = 0
I then set up a loop that adds 1 every second:
while true do
wait(1)
Number = Number + 1
print(Number)
This would output: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, ....
I want this output to be: 01, 02, 03, 04, 05, 06, 07, 08, 09, 10, 11, 12, ..., where there is a 0 before every number less than 10.
How would I do this?
0
You wouldn't be editing the actual number, just the string you are printing. You would simply type print("0"...tostring(Number)). Whenever you wish to incorporate a variables and a string together, use ... in between them. PreciseLogic 271 — 6y
1 answer
Log in to vote
0
You could do a simple "if" statement.
local Number = 0
while true do
wait(1)
Number = Number + 1
if Number < 10 then -- if number is less than 10 (1-9)
print("0"..Number) --Just manually add it.
else --If number is greater than 10 (10 + )
print(Number)
end
end
0
Wow. I didn't expect it to be that simple... shadow7692 69 — 6y