local table = {"hi!", "how", "are", "you", "doing", "on", "this", "fine", "day?"};
while wait(5) do -- loop a
for i,v in pairs(table) do -- loop b
print(v)
if i == #table - 1 then
-- break loop A?
end
end
end
Inside of loop B, I want to break loop A, which loop B is inside of. How would I go about doing this?
Unfortunately, there's not a clean way to do this.
You would have to create some sort of flag that the upper levels use:
local breakA = false;
local table = {"hi!", "how", "are", "you", "doing", "on", "this", "fine", "day?"};
while wait(5) do -- loop A
for i,v in pairs(table) do -- loop B
print(v)
if i == #table - 1 then
breakA = true; -- When we exit B,
-- it will break A
break; -- Breaks out of B
end
end
if breakA then
break;
end
end
You shouldn't require this sort of architecture frequently, however. Usually if you're running into this, there's a cleaner way to organize your code.
First of all, it's hard to tell what you are trying to achieve with this double loop structure, because even if you did "double break" from inside loop B, you could produce functionally identical results with just:
local table = {"hi!", "how", "are", "you", "doing", "on", "this", "fine", "day?"};
for i,v in pairs(table) do
print(v)
if i == #table - 1 then break end --I think you'd want just #table, too, Lua table indices begin at 1 instead of 0
end
end
But to answer your question (EDIT: As @BlueTaslem expresses), you'd need to flag a local boolean variable to indicate that a break was necessary:
local table = {"hi!", "how", "are", "you", "doing", "on", "this", "fine", "day?"};
while wait(0.25) do -- loop a
local b = false --break flag
for i,v in pairs(table) do -- loop b
print(v)
if i == #table - 1 then
b = true
break
end
end
if b then break end
end
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