Count unknown values in a table and list the one that appears the most?

#What you could do Make a dictionary. Dictionaries are tables with custom keys. You could make the keys the answer choices and the values the amount of times they're selected.

#Dictionaries When you make a dictionary you'd make you custom key by surrounding what would be your key with square brackets []. Your key itself can be any lua value. Such as a float, boolean or even an object. As long as it isn't nil. And since a string isn't nil we can use it!

local t = {["Key"]}

Now we need to set the key's value. We'll set it to 0 in this example.

local t = {["Key"] = 0}

Now whenever we check the value for Key, we'll get 0.

print(t["Key"])

0

#Final Product

local exampledatastore = Datastore:GetDataStore(example)
--[[
In this example you've saved all the tables in one datastore
by saving multiple tables into one single table
datastore = {{["Key"] = true},{["Key"] = false}}
^^Kind of like that
]]

ExampleTable1 = {} --"Hi", "Hi", "Hi", "Bye", "Bye"
ExampleTable2 = {} --"Funny", "Funny", "Not Funny", "Not Funny", "Not Funny"
ExampleTable3 = {} --"12", "12", "1", "12", "1"

for table,v in pairs(exampledatastore) do
	if table == 1 then
		for key,value in pairs(exampledatastore[v]) do
			ExampleTable1[key] = value
		end
	elseif table == 2 then
		for key,value in pairs(exampledatastore[v]) do
			ExampleTable2[key] = value
		end
	else
		for key,value in pairs(exampledatastore[v]) do
			ExampleTable3[key] = value
		end
	end
end

popularanswer = {} --Set the table to find all the most popular answer(Just incase multiple answers have the same amount of clicks.)

--We'll use math.max to find out the highest value from each table. Probably a better way to do it than this.
number = 0

for i,v in pairs(ExampleTable1) do
	number = math.max(number,v)
	table.insert(popularanswer,i)
end

number = 0
for _,v in pairs(ExampleTable2) do
	number = math.max(number,v)
	table.insert(popularanswer,i)
end

number = 0
for _,v in pairs(ExampleTable3) do
	number = math.max(number,v)
	table.insert(popularanswer,i)
end

print("The most popular answers were as follows: "..table.concat(popularanswer, ", ")..".")

Hope it helps!