How can i get it to remove only 3 tools i want it to remove
for i,v in pairs(game.Players:GetChildren()) do --Get all children of players
Backpack = v:FindFirstChild("Backpack",true)
if Backpack ~= nil then --Check if the child has a backpack
c = Backpack:GetChildren() --Get the children of the backpack
for i = 1,#c do
c[i]:Destroy() --Use Destroy method instead
end
end
end)
Here You are. EXAMPLE 1: You want to remove only some tools, defined by names It will remove "ToolName1" and "ToolName2" from BackPack
-- SETTINGS
local toremove = {"ToolName1", "ToolName2"} -- NAMES OF TOOLS TO REMOVE
local players = game.Players:GetChildren() -- HERE PLACE ARRAY HOLDING PLAYERS OR PLAYER INSTANCE WHICH WILL LOSE HIS TOOLS
-- SCRIPT
function RemoveFromBackpack(bp)
for _, i in pairs(toremove) do
if bp:FindFirstChild(i) then
bp[i]:Destroy()
end
end
end
if type(players) == "table" then
for _, i in pairs(players) do
if i:FindFirstChild("Backpack") then
RemoveFromBackpack(i.Backpack)
end
end
else
if players:FindFirstChild("Backpack") then
RemoveFromBackpack(players.Backpack)
end
end
EXAMPLE 2: You want only to remove some count of tools It will remove 3 tools from backpack
-- SETTINGS
local count = 3 -- HOW MUCH TOOLS WILL BE REMOVED
local players = game.Players:GetChildren() -- HERE PLACE ARRAY HOLDING PLAYERS OR PLAYER INSTANCE WHICH WILL LOSE HIS TOOLS
-- SCRIPT
function RemoveFromBackpack(bp)
for i = 1, count, 1 do
if bp:GetChildren()[i] ~= nil then
bp:GetChildren()[i]:Destroy()
end
end
if type(players) == "table" then
for _, i in pairs(players) do
if i:FindFirstChild("Backpack") then
RemoveFromBackpack(i.Backpack)
end
end
else
if players:FindFirstChild("Backpack") then
RemoveFromBackpack(players.Backpack)
end
end
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