Hi, I've started working on lua recently, and I was trying to create a script that tells you how many items are in your inventory. I came across an issue; whenever I run the script it outputs as 1, 2.
inventory={"Sword","Arrow"}
function many()
for k,v in pairs(inventory) do
print (k)
end
end
many()
I was wondering how to ONLY print out 2, or the last index number of the table. Thanks in advance.
#What you can do I know this was answered twice already and this is also 19 hours old but there is a MUCH more simpler way to get the number of items inside of a table.
#Operators There are many types of operators that are distributed into 4 categories:
local table = {1, nil, {"Red","String"}, true, workspace.BasePlate, BrickColor.new(1), CFrame.new()}
--These are all different values, also the operation counts tables inside of the ones being counted as a single object, excluding the things, or in this case strings, inside of the 2nd table.
print(#table)
7
It prints "7" because there are 7 things inside of the table. This is perfect for your inventory script.
#Final Product I know the explanation was long, but your modified script will be short, very short.
inventory={"Sword","Arrow"}
print(#inventory)
2
#Hope it helps!
##Extras Here's a quick function I made that will print the amount of things inside of any table:
function readtable(x)
if type(x) == "function" then --If x is a table then...
return #x
end
end
readtable([Insert Table here]) --It will return the length of a table(Note, returning and printing aren't the same thing)
If the table is formatted as an array then the length of that table, #inventory, is always its last key. So to get its associated value, it's as simple as inventory[#inventory].
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