I have a math.floor script which rounds the number and adds SI prefixes at the end, but im trying to figure out to leave 2 decimals remaining. For example 1240.1245435, would be 1.24k+, instead of 1k+. Please help!
local plr = game.Players.LocalPlayer
local lstats = plr:WaitForChild("leaderstats")
local doritos = lstats:WaitForChild("Doritos")
local coinslabel = script.Parent
while true do -- always add bigger numbers first
wait()
if doritos.Value >= 1000000000000000000000000000 then
coinslabel.Text = math.floor(doritos.Value / 1000000000000000000000000000) .. "o+ Doritos!" -- 1,000,000,000,000,000,000,000,000,000 / 1o+
elseif doritos.Value >= 1000000000000000000000000 then
coinslabel.Text = math.floor(doritos.Value / 1000000000000000000000000) .. "sp+ Doritos!" -- 1,000,000,000,000,000,000,000,000 / 1sp+
elseif doritos.Value >= 1000000000000000000000 then
coinslabel.Text = math.floor(doritos.Value / 1000000000000000000000) .. "sx+ Doritos!" -- 1,000,000,000,000,000,000,000 / 1sx+
elseif doritos.Value >= 1000000000000000000 then
coinslabel.Text = math.floor(doritos.Value / 1000000000000000000) .. "qn+ Doritos!" -- 1,000,000,000,000,000,000 / 1qn+
elseif doritos.Value >= 1000000000000000 then
coinslabel.Text = math.floor(doritos.Value / 1000000000000000) .. "qd+ Doritos!" -- 1,000,000,000,000,000 / 1qd+
elseif doritos.Value >= 1000000000000 then
coinslabel.Text = math.floor(doritos.Value / 1000000000000) .. "t+ Doritos!" -- 1,000,000,000,000 / 1t+
elseif doritos.Value >= 1000000000 then
coinslabel.Text = math.floor(doritos.Value / 1000000000) .. "b+ Doritos!" -- 1,000,000,000 / 1b+
elseif doritos.Value >= 1000000 then
coinslabel.Text = math.floor(doritos.Value / 1000000) .. "m+ Doritos!" -- 1,000,000 / 1m+
elseif doritos.Value >= 1000 then
coinslabel.Text = math.floor(doritos.Value / 1000 ) .. "k+ Doritos!" -- 1,000 / 1k+
elseif doritos.Value <= 1000 then
coinslabel.Text = doritos.Value .. " Doritos!" -- <1,000 / <1k+
end
end
3 comments
math.floor(x / .01) * .00001 would be for 1k?
Close, but the goal is to shift the decimal place over to the right to the length of precision you want. This is done in his division operation, where he divides by the number of decimal places you desire. In this case, the tenths place (2 decimals). You simply copy whatever you multiply by, over to whatever you divide by. It cancels out.
For 1k: math.floor(x / .00001) * .00001