Loops, operators, table manipulation help?

Alright, this is supposed to go get a value in a gui in all players, and set it in a table, then go through the table and take out every number except the highest number, and then clone the players head with the highest number, righ now its either not removing the numbers from the table or my logic is wrong, the updated version of the code has been edited on this please help

numtble = {}

function Check()
repeat wait() until game.Players.NumPlayers >= 2
for i,v in pairs(game.Players:GetPlayers()) do
table.insert(numtble,v.PlayerGui.Points.Posy.Numbers.Value)
wait()
print("Awesome2")
wait()
end
end

function Check2()
for i=1, #numtble do
if i > 2 then 
if numtble[i] > numtble[i] - i then 
dum = numtble[i] - 1
table.remove(numtble,dum)
elseif numtble[i] < numtble[i] - i then 
table.remove(numtble,numtble[i])
wait()
print("Awesome")
wait()
end
end
end
end

function Winner()
Check()
Check2()
for i,v in pairs(game.Players:GetPlayers()) do
if v.PlayerGui:findFirstChild("Points"):findFirstChild("Posy"):findFirstChild("Numbers").Value == numtble[1] then

v.Character.Head:Clone().Parent = game.Workspace
wait()
end
end
end

Winner()

I highly recommend picking more descriptive names for your functions. It makes it much simpler to understand and write code.

I believe the problem is in your Check2 function. There are several large problems with it. I will note them here, however, my real suggestion is to completely rewrite Check2.

1. numtble[i] > numtble[i] - i is algebraically equivalent to 0 > -i (which will never be true). I don't really know what you meant to be doing here.

2. table.remove(numtble,numtble[i]) table.remove does not take an element to remove, it takes an index, so to delete the ith element, the second argument should be i, not sometable[i].

First, we note that Check1 does not really provide anything new. The information it gives is already available in a list, :GetPlayers(), it's just useful for us to be able to delete to have it in a copy.

Now, Check2 simply eliminates everything from the list that Check1 makes, ideally leaving only the largest element. In other words, Check2 just finds the largest element in a list.

We can redefine Check2 to work in a much simpler way:

function FindLargest(list) 
	-- For reusability, safety, should be an
	-- argument, rather than a global variable.

	local largest = list[1];
	for i = 2, #list do
		if largest < list[i] then
			largest = list[i];
		end
	end
	return largest; -- I am choosing to return instead of
	-- modifying numtbl, because it is cleaner and safer.
end

Our Winner function now looks like this:

function Winner()
	Check()
	local best = FindLargest(numtbl);
	for i,v in pairs(game.Players:GetPlayers()) do
		if v.PlayerGui:findFirstChild("Points"):findFirstChild("Posy"):findFirstChild("Numbers").Value == best then
			v.Character.Head:Clone().Parent = game.Workspace
			wait()
		end
	end
end

I highly recommend changing the name of Check to GetPlayerScores or something similar. I also recommend making it return the list rather than just set it to a value. Then we would have the Winner function begin like this:

local best = FindLargest(GetPlayerScores());