It is possible to call a function with the use of arithmetic?

function exeC(func)
	func()
end

while true do
	for i = 1, 10 do
		LO()
		local L = "L"
		local N = i-1
		local LN = L..N
		local LNf = LN.."()"
		wait(0.01)
		print(LNf) -- Used in checking...
		exeC(LNf)
		wait(0.99)
	end
end

What I wanted to happen is to call a function with the use of arithmetic. I find it messy to call a function with lots of if statements (Assigning i value to each function). I have functions named L0 - L9. Is it possible to call a function with arithmetic to match the function's name? e.g (L0 : "L"..[i], i = 0)

I would appreciate your response/answer/help.

You can technically get away with this by using setfenv to modify the environment of your script, but I'd recommend using a table of functions instead since modifying the script environment is pretty nasty and will also give you tons of warning squiggles.

Table of functions:

local L = {}
for i=0,9 do
    L[i] = func
end

print(L[0]())

setfenv

local env = getfenv(1)--make sure we keep track of the stuff in the current env like script/etc
env["L0"] = function() return 3 end
setfenv(1, env)

print(L0())--L0 will work, but it'll have a warning squiggle since it wasn't properly defined in the script