Why are both 'If' statements activating?

Let's begin with the first error,

• The or function,

Basically, if you have use an or statement with a conditional statement, it will check if both values are nil, and if they are, the code after doesn't run. For example,

local x = "y"

if x == "x" or x == "y" then
	print("X = x or y ")
end

---------------------

OUTPUT,

X = x or y

So let's use the ~= operation. This checks if something is not something, as you probably know.

local x = "y"

if x ~= "x" or x ~= "y" then
	print("X = x or y ")
end

The output would ALWAYS be the same, no matter the value of x. I hope you understand why.

Simple fix,

Use an else statement.

So if the first conditional returns false, the second knows, and can interpret the information.

Admins = {}     -- Up to 3 Admins
Children = {} -- Do not touch



function Children(player) -- This will turn everyone who isn't part of the list into children
	local Player = player:GetFullName()
	print(player)
	if Player.UserID == Admins[1] or Player.UserID == Admins[2] or Player.UserID == Admins[3] then
		print("DayCareWorker")
	else
		print("Child")
	end
end     

game.Players.PlayerAdded:connect(Children)

There, now onto the

Second problem,

You're trying to access the UserId of the String, the player's name, not the player. Also, I'm not sure but I think it's userId, not UserID. That part probably doesn't matter, but I'm changing it anyways,

Admins = {}     -- Up to 3 Admins
Children = {} -- Do not touch

function Children(Player) -- This will turn everyone who isn't part of the list into children
	if Player.userId == Admins[1] or Player.userId == Admins[2] or Player.userId == Admins[3] then
		print("DayCareWorker")
	else
		print("Child")
	end
end     

game.Players.PlayerAdded:connect(Children)

Third problem,

I don't think this is your script, but who ever you stole/took it from, sucks at scripting. I'm removing the Children variable because it has no point. Yes, I'm touching it.

Admins = {}     -- Up to 3 Admins-- Which is stupid

function Children(Player) 
	if Player.userId == Admins[1] or Player.userId == Admins[2] or Player.userId == Admins[3] then
		print("DayCareWorker")
	else
		print("Child")
	end
end     

game.Players.PlayerAdded:connect(Children)

Final Note,

I would recommend you use a loop to check if people are on the list of being an admin, because you can add as many people as you want and it would be much better overall. Also, your name is always Player/Player1 when you're testing in studio.

Good Luck!

If I helped, please don't forget to hit the accept answer button next to my answer. It helps a lot.