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✓ ANSWER ACCEPTED

How can I start this function when a GUI is visible?

Asked 408 views1 answers

I have this simple part of a script 

wait(5)
if FRAME.Visible == true then 
 repeat 
	wait(3)check_Have() print("checking...")
	until 
	FRAME.Visible == false	
end

Which does what I want it to, it runs the check_Have() function if the frame is visible after the 5 second wait, but I want it to be able to recognize when the FRAME goes from not visible to visible. Basically this works for when the frame is already visible but not for when it becomes visible after the 5 seconds. How would I notify the script that the frame has become visible?

Anonymous

3 comments

0

Do you mean only if it's changed from not visible to visible?

Anonymous#
0

Couldn't you just use FRAME.Changed:print("The frame has changed")? That's just an idea, as I don't quite understand your question.

Anonymous#
0

sorry I should have been more clear. When I said "notify the script" I mean't write in Lua what I want the script to do. Basically my question is how do I tell the script that when the frame BECOMES visible I want it to do the check_Have() function

Anonymous#

1 answer

✓ Accepted answer
FRAME.Changed:connect(function(prop)
	if prop == 'Visible' and frame.Visible == true then
		repeat
			wait(3) 
			check_Have()
			print('Checking...')
		until FRAME.Visible == false
	end
end)

I assume this is what you meant. The Changed event fires when a property of the frame changes and gives you a string containing the name of the property, in this case prop. It then checks that the visibility changed to true and if it did it then does your repeat loop.

AnonymousPermalink

1 comment

0

Perfect! thank you so much!

Anonymous#

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