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✓ ANSWER ACCEPTED

Is there a way around this?

Asked 225 views1 answers

I'm trying to make a script that can exceed the default values of a ROBLOX leaderboard, it was successful until I tried to add quadrillions, I know it's possible because I've seen games do it but every time I use the following script I get the value (only when it gets to quadrillions)

1e+.0k

This is the script: (any help is appreciated)

function ConvertShort(num, cool)
    local x = tostring(num)
	if #x >= 16 then
		local important = (#x - 15)
		cool.Value = x:sub(0,(important)).."."..(x:sub(#x-13,(#x-13))).."qd"
    elseif #x >= 13 then
		local important = (#x-12)
        cool.Value = x:sub(0,(important)).."."..(x:sub(#x-10,(#x-10))).."T"
    elseif #x>= 10 then
		local important = (#x - 9)
		 cool.Value = x:sub(0,(important)).."."..(x:sub(#x-7,(#x-7))).."B"
    elseif #x >= 7 then
        local important = (#x-6)
        cool.Value = x:sub(0,(important)).."."..(x:sub(#x-5,(#x-5))).."M"
    elseif #x >= 4 then
        cool.Value =  x:sub(0,(#x-3)).."."..(x:sub(#x-2,(#x-2))).."k"
    end
end

game.Players.PlayerAdded:connect(function(plr)
    local cash = Instance.new("StringValue", plr)
    cash.Name = "cash"
    cash.Value = "0"
    cash.Changed:connect(function()
      		ConvertShort(tonumber(cash.Value), cash)
    end)
end)
AnonymousEdited

3 comments

0

I don't have a fix for this, but I do have a working(for any size number) script to shorten the number. Do you need to use this script? Or can I answer with mine.

Anonymous#
0

you can answer with yours as long as it shortens any number

Anonymous#
0

answering

Anonymous#

1 answer

✓ Accepted answer
local letters = {
	"K",
	"M",
	"B",
	"T",
	"QD",
	"QN",
	"SX",
	"SP",
	"O",
	"NO",
	"DEC",
	"UND",
	"DUOD",
	"TRED",
	"QUATD",
	"QND",
	"SXD",
	"SPD",
	"OD",
	"NOVD", -- I really doubt somebody will get more than a novemdecillion
	--put more here
}
local nums = {}

for q=1,#letters do
	local dig = (q*3)+1 --digits
	local letter = 1*(10^(dig-1)) --for dividing purposes
	table.insert(nums,#nums+1,letter) --insert
end

function shorten(num)
	local len = math.ceil(math.log10(num + .5)) --get the digits
	if len>=4 then --check if it's ok to shorten
		for q=1,#letters do
			local dig = (q*3)+1 --smallest number of digits the letter is
			if len <= dig+2 then --check if this digit works
				local toDo = math.floor(num/nums[q]) --the dividing number
				local newNum = toDo..letters[q] --the new num
				return newNum --return it
			end
		end
	end
end

print(shorten(1789000000000000000))--it returns the shortened num
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