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✓ ANSWER ACCEPTED

Changing color + material script?

Asked 215 views1 answers
p = workspace:GetChildren() 
for i=1, #p do 
if p[i].className == "Part" or "Wedge" then
if p[i].BrickColor == BrickColor.new("White") and p[i].Material == "Slate" then
p[i].BrickColor = BrickColor.new("Grime")
p[i].Material = "Grass"
		end
	end
end

The problem I'm running into is that there are models in the workspace, and BrickColor & Material are not characteristics of Models.

So if you don't understand, I need this script to change any part or wedge that is colored white, and has the material called Slate.. except it also attempts to change the models in the workspace.

Anonymous

1 comment

0

Your error was or "wedge", you needed to put p[i].className == "Wedge" although :IsA("BasePart") is a better alternative.

Anonymous#

1 answer

✓ Accepted answer
for _,v in pairs (workspace:GetChildren())
	if v:IsA("BasePart") then
		if v.BrickColor == BrickColor.new("White") and v.Material == "Slate" then
			v.BrickColor = BrickColor.new("Grime")
			v.Material = "Grass"
		end
	end
end

"Your error was or "wedge", you needed to put p[i].className == "Wedge" although :IsA("BasePart") is a better alternative." -DevSean

And I changed the for loop to a generic one just because I prefer it over numeric when working with objects.

AnonymousEdited Permalink

2 comments

0

Don't just past code, explain what was wrong and why your code works.

Anonymous#
0

didn't have time to do that at the time.

Anonymous#

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