What do you need to do ?
A for loop ? math.random() ?
Some help on here please.
✓ ANSWER ACCEPTED
How would you make a randomized chance to spawn for example a golden brick?
3 answers
✓ Accepted answer
math.random()
If you wanted it to be, say, a 1 in 5 chance:
if math.random() <= 1/5 then
-- Boom, golden brick!
end
I mean, I myself would use Int Values and math.random
if math.random(1, 100) <= script.Chance.Value then
1 comment
0
Will not quite work as expected if Chance is a decimal value. math.random generates integers. If chance was set to 1.99 (1.99%), it would effectively have a 1% probability of occurring. Furthermore, chances under 1% will always have a 0% probability of occurring.
Another way of solving this is to have some sort of rarity variable, where a golden brick has a 1 in rarity chance of appearing. Making the rarity of the brick bigger means that it is more rare!
local GOLDEN_BRICK_RARITY = 100 -- this means that 1 in 100 bricks spawned will be golden. Setting this to 1 means a golden brick will ALWAYS spawn.
function SpawnBrick()
if math.random(1, GOLDEN_BRICK_RARITY) == 1 then
-- TODO: Spawn a golden brick
else
-- TODO: Spawn a regular brick.
end
This discussion is preserved as it was. New answers, comments, and votes are closed.
1 comment
math.random(1,chance)would be your best bet.