if("Jon".length * 2 / (2+1) == 2 ) { console.log("The answer makes sense") } else if("jon".length * 2 / (2+1) >=2) { console.log("the answer is nagative") }
and is this there another way the script can be chaged
✓ ANSWER ACCEPTED
Is this the right coding?
1 answer
✓ Accepted answer
What you're writing is JavaScript. Here's how you could do the above in Lua.
if(string.len("Jon") * 2 / (2+1) == 2) then
print("The answer makes sense")
elseif(string.len("jon") * 2 / (2+1) >= 2) then
print("the answer is nagative")
end
Syntax-wise, rather than { and } brackets, which are used in many OOP languages like JavaScript, Lua uses a replacement for these in most cases...
{ can be a few keywords, like then, do, and others.
} is usually end, though it isn't used after each part of an if statement.
Good luck! I hope this helps.
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