I tried to remove a player with a variable of alien from a table called playersin as shown:
table.remove(playersin, alien)
(The Rest of the Script works perfectly fine)
The output shows me this:
16:58:55.598 - ServerScriptService.Game.G:148: bad argument #2 to 'remove' (number expected, got Object)
What does this mean?
The table.remove function only removes values from a list. It will not search through the table looking for the value to match the second argument. It looks for the key, which is suppose to be a number.
Example:
local list = {
"pie",
"ice cream",
"candy",
}
table.remove(list, 2) -- this will remove "ice cream" because it's index value is 2.
If you want to make it so you remove a value from a table based on it's value, you can write a separate function that compares every value in the table to an argument you give it.
Like this:
local list = {
"pie",
"ice cream",
"candy",
}
local function remove_value(Table, Value)
for i,v in pairs (Table) do
if v==Value then
table.remove(Table,i)
end
end
end
remove_value(list, "pie")
print(unpack(list)) -- > "ice cream" , "candy"
This discussion is preserved as it was. New answers, comments, and votes are closed.
7 comments
So how will I remove a certain, randomized player?
wrong. you can remove variables too
I updated the answer. Try using that function.
No dav, you cannot remove a value from a dictionary using table.remove() alone.
Thank you so much!
values you cant, variable you can
I don't think we're on the same page here. Could you give an example of what you mean?