I was wondering how I could know if something is in a table, like:
List = {"Blah" , "Bloop" , "BSI"}
if List:FindFirstChild("Blah") then
--do whatever
end
✓ ANSWER ACCEPTED
Functions with tables?
2 answers
✓ Accepted answer
You can use a for loop to iterate throughout the table.
function InTable(Tab,Value)
for _,n in pairs(Tab) do
if n == Value then
return true
end
end
end
List = {"Blah" , "Bloop" , "BSI"}
if InTable(List,"Blah") then
--Stuff
end
You could place the function inside the table to use it as a method:
List = {"Blah" , "Bloop" , "BSI"}
function List:Find(Value)
for _,n in pairs(List) do
if n == Value then
return true
end
end
end
if List:Find("Blah") then
--Stuff
end
If you wanted a generic function you could place into any table you could use metatables.(Without having to modify the function)
local FindMeta = {
__index = function(self,key)
if key == "Find" then
return function(Value)
for _,n in pairs(self) do
if Value ==n then
return true
end
end
end
end
end
}
List = {"Blah" , "Bloop" , "BSI"}
setmetatable(List,FindMeta)
List2 = {"Blah" , "Bloop" , "BSI"}
setmetatable(List2,FindMeta)
if List.Find("Blah") and List2.Find("Bloop") then
--Stuff
end
2 comments
0
Should MetaTables have List:Find or List.Find? I thougt List.Find() tends not to accept parmaters.
0
@RM0d: List:Find() just means "List.Find(List)". Thus, on line 19, it should be either 'List.Find(List, "Blah")' or 'List:Find("Blah")'
It is generally more efficient to use dictionaries instead of repeatedly searching through a list. If you start with a list, you can convert it into a dictionary (though you only save time if you save the Dictionary for use later instead of recreating it every time you want to use it)
List = {"Blah" , "Bloop" , "BSI"}
Dictionary = {}
--Convert List to Dictionary
for i = 1, #List do
Dictionary[List[i]] = true
end
--Use Dictionary instead of List from now on.
--To add: Dictionary["newItem"] = true
--To remove: Dictionary["itemToRemove"] = nil
if Dictionary["Blah"] then
--do whatever
end
--To go over the list:
for k,v in pairs(Dictionary) do
--'k' is the variable of interest (ex it will contain "Blah", "Bloop", etc), 'v' will just hold 'true'
end
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1 comment
What did I do to deserve a vote down?