My error : bad argument #2 to 'remove' (number expected, got table)
Settings = {
Ranked = { -- 3=Owner, 2=Admin, 1=Member, 0=nil, -.5=Muted, -1=Banned
{Name = "Player",Rank = 3};
{Name = "Idiot",Rank = -.5};
},
}
for _,v in pairs(Settings.Ranked) do
local msg = msg:lower()
local sub = msg:sub(7)
local data = v.Name:lower()
local num = tonumber(-.5)
if msg == 'all' and v.Rank == num or data:find(sub) and v.Rank == num then
table.remove(Settings.Ranked, v) -- Error here
end
end
v refers to the rank data. _ refers to the key/index.
The simple solution to that would be replacing table.remove(Settings.Ranked, v) by table.remove(Settings.Ranked, _), but that messes everything up because it's in the middle of a loop.
Instead, if you don't want any holes inside the table indices (it may be better to use the rank info as the key itself instead and simply set the value to true, but it may be a bit late for that now), you could try doing this:
local temp = {}
for _,v in pairs(Settings.Ranked) do
local msg = msg:lower()
local sub = msg:sub(7)
local data = v.Name:lower()
local num = tonumber(-.5)
if msg == 'all' and v.Rank == num or data:find(sub) and v.Rank == num then
temp[#temp + 1] = _
end
end
for i,v in ipairs(temp) do
table.remove(Settings.Ranked, v + 1 - i) -- `+ 1 - i` is to accomodate for the removed indices.
end
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1 comment
I tryed v[1] but it wouldnt remove the correct ban.