I fixed it on my own, but thanks for the support. None of the answers really helped so I made my own workaround that works perfect.
COMMUNITY QUESTION
[SOLVED] How can I call the last two values of a table?
2 answers
Yes, that is easy. To call something in a table you need to do something like this:
mytable = {1,2,3,4,5,6,7,8,9,1337, "Roblox"}
print(mytable[10]) --Should print "1337".
Now to call the last thing in the table do this:
mytable = {1,2,3,4,5,6,7,8,9,1337, "Roblox"}
print(mytable[#mytable]) --Print the 11th one since there are only 11 of them.
To do the second to last one do this:
mytable = {1,2,3,4,5,6,7,8,9,1337, "Roblox"}
print(mytable[(#mytable-1)]) --Should print "1337", 11-1= 10 which is the 2nd to last one on the table.
There, that is all!
3 comments
0
Let's say the table is constantly being added to, new numbers each time at the end, and I want to print() the last two every time. Only one would be added at a time. How would I call them THEN, same method?
0
@ iiFirestorm Yes.
0
Still problems. It doesn't seem to find the second to last, but does find the last. table.insert(fs, table.maxn(fs)+#fs-1)
local tab = {0,1,2}
for i = 1,10,1 do
table.insert(tab,1,i)
local last = tab[#tab] --#table returns the length of the table as an integer
local secondlast = tab[#tab - 1]
local first = tab[1]
print(last, secondlast, first)
wait(1)
end
4 comments
0
should work for a loop
0
Thanks for your support, but it didn't work.
0
really? worked for me. I made this on my phone by the way, so I'll edit my answer soon
0
That one works fine for me.
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1 comment
@ iiFirestorm Yes to your question.