How to check if one of two values have not yet been enabled after 230 secs or before?

The logic flow you need is this:

1. Connect to all the events you want to listen to. Be sure to either only connect once or else disconnect from them when you no longer need them. Whenever any of them fire, do whatever you would like to do in response, but also make sure you've recorded in a variable that one of these events has taken place. Make sure this prevents the other event handlers from doing anything, if appropriate.
2. Wait for 230 seconds.
3. If no event handlers have been run, then run the default behaviour (whatever you want to have happen after 230 seconds if no event has fired)

-- Example using arbitrary events for demonstration
local win = Instance.new("BindableEvent")
local loss = Instance.new("BindableEvent")

local function play()
	local victory, defeat
	local winCon = win.Event:Connect(function()
		victory = true
		print("Victory!")
	end)
	local lossCon = loss.Event:Connect(function()
		defeat = true
		print("Defeat!")
	end)
	wait() -- short game :)
	if not victory and not defeat then
		print("Timed out.")
	end
	winCon:Disconnect()
	lossCon:Disconnect()
end
for num = 1, 3 do
	print("Round", num)
	task.spawn(play) -- Think of this as the same as "play()" except that it happens on a new thread, so we don't wait for it to finish when it waits.
	-- local num = math.random(1, 3) -- Tip: always save this to a variable first or else you'll get a different number each time you call it. I've got this disabled (and am using the for loop) so you can see all 3 outcomes quickly.
	if num == 1 then
		win:Fire()
	elseif num == 2 then
		loss:Fire()
	end
	wait(0.2)
end