So Im starting on a game where you go around tame animals then you can turn into them. I just dont know how to set up a tame chanse like. If the tame chanse is 80% how to I make it theres only 20% of the tame failing? Thank you in advanced.
✓ ANSWER ACCEPTED
How to make a tame chance system?
2 answers
✓ Accepted answer
local Chance= 80
local Tamed = 0
local Nope = 0
while true do
local Percent= math.floor( (math.random()*100)+0.5) -- Custom Round since Lua don't have a math.round function!
if(Percent <= Chance) then
Tamed = Tamed + 1
else
Nope = Nope + 1
end
print("Tame Success =", Tamed," : Nope = ", Nope)
wait()
end
The above script will print out how many times it succeeds and how many times it fails. The only bit you need is
local Chance= 80
local Percent= math.floor( (math.random()*100)+0.5) -- Custom Round since Lua don't have a math.round function!
if(Percent<= Chance) then
-- Do stuff on Tamed!
end
I just made the script loop through possible rolls as if you're trying with an unlimited amount of tries.
Hope this helps! :)
Here this should help. I'm not that advanced so Im not sure how to shorten the 'or' statement lol sorry. Also instead of the prints put the script that makes it tamed or not.
local randomnumber = math.random(1,100)
print(randomnumber)
if randomnumber == 1 or randomnumber == 2 or randomnumber == 3 or randomnumber == 4 or randomnumber == 5 or randomnumber == 6 or randomnumber == 7 or randomnumber == 8 or randomnumber == 9 or randomnumber == 10 or randomnumber == 11 or randomnumber == 12 or randomnumber == 13 or randomnumber == 14 or randomnumber == 15 or randomnumber == 16 or randomnumber == 17 or randomnumber == 18 or randomnumber == 19 or randomnumber == 20 then
print("Failed")
else
print("Tamed")
end
This discussion is preserved as it was. New answers, comments, and votes are closed.
2 comments
Also copy it from the source
Instead of all the inefficient if/or statements, why not just do
if randomnumber <= 20 then... It'll do the same thing.