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✓ ANSWER ACCEPTED

Why can not get model's humanoid through its name?

Asked 202 views1 answers

I try to make a commanding model, but it doesn't seem to get the model's Humanoid.\

local rp = game:GetService("ReplicatedStorage")
local remote = rp:FindFirstChild("Z")



remote.OnServerEvent:Connect(function(player, val, Mouse)


	if val == "CommandZombie" then
		local Zombiepet = workspace:GetChildren(player.Name.."'s Pet")
		local zomNoid = Zombiepet:FindFirstChild("HumanoidRootPart")
		print(("ZOmbieeeeeee"))
		if Zombiepet and zomNoid then
			print(("ZOmbie"))
			local bodyposition = Instance.new("BodyPosition")
			bodyposition.Parent = zomNoid 
			bodyposition.MaxForce = Vector3.new(10000,10000,10000)
			Zombiepet.Position = Mouse
			game.Debris:AddItem(bodyposition, 4)
		end

	end
end)
AnonymousEdited

1 comment

0

GetChildren() doesn't have parameters and returns a table. You can give it anything you want and it won't matter, because there are no parameters to give arguments to; GetChildren() will still give you a table of every child under Workspace. Either use FindFirstChild()/WaitForChild() or loop through the existing table.

Anonymous#

1 answer

✓ Accepted answer

On line 10, workspace function GetChildren (https://developer.roblox.com/en-us/api-reference/function/Instance/GetChildren) returns an array of children parented under workspace. In this case, the arguments wouldn't have any change on the returned values. (Note: this applies to some functions.)

I suggest changing GetChildren to FindFirstChild.

Sample script proving that the arguments of GetChildren have no influence on the returned values.

local workspace = workspace

local t1 = workspace:GetChildren()
local t2 = workspace:GetChildren('wow potato')

for a=1,#t1 do
	print(t1[a]==t2[a]) -- true
end
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