Why does the block just sit in place and not change a thing?

I cant runt he script in studio to see the error becuz it will crash studio :/

Script is supposed to assign a name to the string value and change text in places and then go down and disappear:

P.S. I DONT LOOP BECAUSE I DONT KNOW HOW TO GET IT TO WORK...I tried, lol

local bo = script.Parent.BecomeOwner
local val = script.Parent.Parent.Owner
local nam = script.Parent.Name
local pos = script.Parent.BecomeOwner.Position

function onTouch(plr)
	val.Value = plr.name
	nam = "Current Owner: " ..val.Value
	bo = Vector3.new (0,-.3,0)
	wait(.1)
	bo = Vector3.new (0,-.3,0)
	wait(.1)
	bo = Vector3.new (0,-.3,0)
	wait(.1)
	bo = Vector3.new (0,-.3,0)
	wait(.1)
	bo = Vector3.new (0,-.3,0)
	wait(.1)
	bo = Vector3.new (0,-.3,0)
	wait(.1)
	bo = Vector3.new (0,-.3,0)
	wait(.1)
	bo = Vector3.new (0,-.3,0)
	wait(.1)
	bo = Vector3.new (0,-.3,0)
	wait(.1)
	bo = Vector3.new (0,-.3,0)
	wait(.1)
	bo = Vector3.new (0,-.3,0)
	wait(.1)
	bo = Vector3.new (0,-.3,0)
	wait(.1)
	bo = Vector3.new (0,-.3,0)
	wait(.1)
	bo = Vector3.new (0,-.3,0)
	wait(.1)
	bo = Vector3.new (0,-.3,0)
	wait(.1)
	bo = Vector3.new (0,-.3,0)
	wait(.1)
	bo = Vector3.new (0,-.3,0)
	wait(.1)
	bo = Vector3.new (0,-.3,0)
	wait(.1)
	bo = Vector3.new (0,-.3,0)
	wait(.1)
	bo = Vector3.new (0,-.3,0)
	wait(.1)
	bo = Vector3.new (0,-.3,0)
	wait(.1)
	bo = Vector3.new (0,-.3,0)
	wait(.1)
	bo = Vector3.new (0,-.3,0)
	wait(.1)
	bo = Vector3.new (0,-.3,0)
	wait(.1)
	bo = Vector3.new (0,-.3,0)
	wait(.1)
	bo = Vector3.new (0,-.3,0)
	wait(.1)
	bo = Vector3.new (0,-.3,0)
	wait(.1)
	bo = Vector3.new (0,-.3,0)
	wait(.1)
	bo = Vector3.new (0,-.3,0)
	wait(.1)
	bo = Vector3.new (0,-.3,0)
	wait(.1)
	bo:Destroy()
end

script.Parent.Touched:connect(onTouch)

To loop, all you would need to do is this:

for i = 1, 10 do -- 10 will be the amount of times it loops

bo = Vector3.new (0,-.3,0)
wait(.1)

end

As for the movement error, it seems like you already figured that out.

If not, you could do something like this--

local posit = 10 -- Whatever the starting X position is.

for i = 1,10 do

posit = posit - .3
bo = Vector3.new(0, posit, 0)
wait(.1)

end