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✓ ANSWER ACCEPTED

Why cant I move this model to a random position?

Asked 268 views1 answers

I am trying to move a model to a random position using math.random() but for some reason I get an error saying "Unable to cast double to Vector3" here is the code:

while PizToClone <= Piztobe do
	local copyPizza = Pizza:Clone()
	copyPizza.Parent = workspace.Pizzas
	copyPizza:MoveTo(math.random(198, 210), 231,math.random(31,41)) --This is the line giving me trouble 
	print(copyPizza.Position.X, copyPizza.Postition.Y, copyPizza.Position.Z)
	PizzaCounter += 1
	print(PizToClone)
	print(PizzaCounter)
end
Anonymous

1 comment

0

Not too familiar with :MoveTo() but doesn't it take a Vector3 as its argument? ex copyPizza:MoveTo(Vector3.new(math.random(198,210), 231, math.random(31, 41))) doc: https://developer.roblox.com/en-us/api-reference/function/Model/MoveTo

Anonymous#

1 answer

✓ Accepted answer

Hello.

The reason that you are experiencing this is because MoveTo expects Vector3.

You are not providing a Vector3, you are simply providing 3 numbers.

You can do this correctly by incasing those numbers with a Vecto3, like so: 

copyPizza:MoveTo(Vector3.new(math.random(198, 210), 231,math.random(31,41)))

Best of luck!

AnonymousPermalink

1 comment

0

Thank you

Anonymous#

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