For example. i have a table
t = {Variant1 = 33, Variant2 = 1, Variant3 = 123, Variant4 = 33}
I need to find the key(s) with highest value(s). So, how can i compare it?
✓ ANSWER ACCEPTED
How can i compare table elements among themselves?
2 answers
✓ Accepted answer
This is how I always do it.
local highest = 0
local t = {Variant1 = 33, Variant2 = 1, Variant3 = 123, Variant4 = 33}
for i,v in pairs(t)do
if v > highest then
highest = v
end
end
print(highest)
This is the most(maybe) solution I can found:
local t ={1, 2, 3}
print(math.max(unpack(t)))
About the randomize, why you need to randomize it when it already the same?
1 comment
0
Not sure if i need exactly this method, but seems it's useful in other situations, so i'll remember it, thank you!
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2 comments
But what if i have 2 same highest? for example var1 = 2, var2 = 5, var3 = 5. I need to randomize the choose between same numbers.
then you can add them to a table and then math.random(1,#Table