How to instantly skip 50 stages but use it only one time?

Let's Say I am in stage 14 I want to be in stage 50 but how could I do it so that the player goes to it but doesn't be able to purchased again

MarketplaceService = Game:GetService("MarketplaceService")

MarketplaceService.ProcessReceipt = function(receiptInfo)
players = game.Players:GetPlayers()

local currency = "Stage"

done = 0

for i=1,#players do
	if players[i].userId == receiptInfo.PlayerId then
		if receiptInfo.ProductId == 967779711 and done == 0 then
			done = 1
			players[i].leaderstats[currency].Value = players[i].leaderstats[currency].Value + 50
			players[i].Character.Humanoid.Health = 0
				done = 0
				
		end
	end
end
return Enum.ProductPurchaseDecision.PurchaseGranted	
end``

local amount
local stagesskipped
local stages = 112 -- the amount of stages the player is at stages
for i = 1,50 do-- 50 is the max amount of times the for statement will have to run
    local number = stages+i
    local end2 = string.sub(number,string.len(number)-1,string.len(number))--this gets the last two numbers of the stage
    if tonumber(end2) == 00 or tonumber(end2) == 50 or tonumber(number) == 0 then amount = number stagesskipped = i end-- if the number ends in 00 50 or the original number is 0 (in case the stage number is negitive)
end
print(amount,stagesskipped)--the amout is the stage of which the player's stage should be at and stageskipped is the amount of stages the player skipped

local amount
local stagesskipped
local stages = -put the players stage here
for i = 1,50 do-- 50 is the max amount of times the for statement will have to run
	local number = stages+i
	local end2 = string.sub(number,string.len(number)-1,string.len(number))--this gets the last two numbers of the stage
	if tonumber(end2) == 00 or tonumber(end2) == 50 or tonumber(number) == 0 then amount = number stagesskipped = i end-- if the number ends in 00 50 or the original number is 0 (in case the stage number is negitive)
end

hope this helped!