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Why wont my feature that works in Studio work in game?

Asked 210 views1 answers

I have a script that clones a part into the CurrentCamera of the player, then when the push a button it destroys the part. I have it like this so it only deletes the part for 1 person, not the whole server. The script looks like this and is inside of a localscript in the StarterGui tab

game.ReplicatedStorage:WaitForChild("Door"):Clone().Parent = workspace.CurrentCamera
local button = workspace.Rooms.VeryEasy.Room2.GreenButton1


-- Create a ClickDetector
local ClickDetector = Instance.new("ClickDetector")
ClickDetector.Parent = button
ClickDetector.MaxActivationDistance = 10
 
-- Open the button on left mouse click
ClickDetector.MouseClick:Connect(function()
	print("work3")
	workspace.CurrentCamera.Door:Destroy()
end)

It creates and destroys the part in Roblox Studio, but it doesn't do the same in the actual game. If anyone needs more info on what I want it to do, its on the second green stage in this game https://www.roblox.com/games/4989653371/Tower-Escape-Pre-Alpha-UPDATE?refPageId=fb5fb20e-4f2a-4cbf-9511-07f4a7127df0 (it takes literally under 30 seconds to get there)

AnonymousEdited

1 answer

✓ Accepted answer
script.Parent.ClickDetector.MouseClick:Connect(function(player)
	script.Parent.RemoteEvent:FireClient(player)
end)

Include this in the part with the clickdetector. When the player clicks it, it will fire the event for the player who clicked it. This is also a normal script. Make sure you also include a remoteevent in the part. 

local Event = workspace.Rooms.VeryEasy.Room2.GreenButton1.RemoteEvent

Event.OnClientEvent:Connect(function(player)
	if workspace.Rooms.VeryEasy.Room2:FindFirstChild("Door") then
	workspace.Rooms.VeryEasy.Room2.Door:Destroy()
end
end)

This script will go into the StarterPlayerScripts. This will be a local script as well. This tells the Event what needs to happen when it is fired. This will delete only the part on the client's side.

Hope this helped!

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