[Solved] How to unpack a dictionary?

unpack only works for tables that are lists (using 1, 2, 3, so on as its indices).

Instead, you'll have to do the maximum calculation yourself, though it isn't very complicated.

You move through each element and determine whether or not it's bigger than the biggest previously seen. If it is, you remember that place as the biggest so-far-seen element. When there's no more elements to check, you have your answer at the so-far biggest.

function findBiggestIndex( tab )
	-- Since you're using a function, it's better for
	-- the table to search in to be an argument.
	-- That way it's easier to repurpose later.
	biggestIndex = nil;
	for index, value in pairs( tab ) do
		if biggestIndex == nil or tab[ biggestIndex ] < value then
			biggestIndex = index;
		end
	end
	return biggestIndex
end

print( findBiggestIndex( test ))
-- high

For the heck of it, here's a function that will unpack all of the values in a table instead of just the ones in list indices:

function unpackall(tab)
	local o = {};
	for i,v in pairs(tab) do
		table.insert(o,v);
	end
	return unpack(o);
end

Though I think using unpack in general isn't usually a good way to go unless it truly makes the code more elegant (in this case I am not sure that it does -- you still need the second loop anyway)