How to do math.random without pulling specific number?

For example, lets say I want to pull a number from 1 - 10. That would be:

math.random(1,10)

However, how would I be able to randomize a number from 1 - 10 but exclude a specific number, like 5?

make a blacklist that contains the numbers that you want to exclude, then iterate through the blacklist to check the random number

local randomNumber = math.random(1,10)
local blacklist = {5,7,3} -- put numbers to exclude here

local fails = {}
local good = false
local oof = false

repeat
	for x = key,number in pairs(blacklist) do
		if randomNumber == number then -- if the random number is in blacklist
			table.insert(fails,false)
			continue
		end

		if not randomNumber == number then -- if the random number is not in blacklist
			continue
		end
	end

	if #fails == 0 then -- if the random number is not in blacklist
		print("Number is good!")
		good = true
	if not #fails == 0 then --  if the random number is blacklisted
		print("Number is bad oof")
		oof = true
until good or oof

Don't accept this answer.

local math = setmetatable({}, {__index = math});

function math.random(a,b, blacklist)
	local randomInt = getmetatable(math).__index.random(a,b);
	if not (table.find(blacklist, randomInt)) then
		return randomInt;
	end
	return math.random(a,b, blacklist)
end

Not to be used in excessiveness, like all random functions. Not performant either, but Jiramide will probably come and fix it for me. This is a better alternative to ProjectInfiniti's answer, so please accept his answer. He had the right idea and the right execution.

people are putting wayyy to complicated stuff

local function check(tbl, thing)
	for _, v in pairs(tbl) do
		if thing == v then
			return true
		end
	end
end
local function randomwithexclude(start, end, excluded)
	local timesdone = 0
	local num
	repeat
		num = math.random(start, end)
		timesdone = timesdone + 1
	until check(excluded, num) ~= true or timesdone == 500 -- returns nil if the function runs 500 times
	if timesdone == 200 then
		return nil
	else
		return num
	end
end

print(randomwithexclude(1, 10, {3, 6, 9})) -- never tested it but it must be a table with values inside

not way too sure if it works. u could replace the timesdone with something else

Hi!

People are creating really complicated answers! I have two very simple solutions:

Solution 1: Reroll Until Not 5

local chosenNumber = math.random(1,10)

while true do
	if chosenNumber == 5 then
		chosenNumber = math.random(1,10)
	else
		break
	end
	wait()
end

This simply chooses a number between 1 and 10. If the result is 5, it will keep on rerolling until it is not 5. Once the variable "chosenNumber" is not 5, the while loop will break.

Solution 2: Random From Table

local avaliableNumbers = {1,2,3,4,6,7,8,9,10}
local chosenNumber = avaliableNumbers[math.random(1, #avaliableNumbers)]

avaliableNumbers is a table that has the numbers 1-10 except for 5. Line 2 chooses a random value from the table.